3[4x-4(y-1)]=

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Solution for 3[4x-4(y-1)]= equation:


Simplifying
3[4x + -4(y + -1)] = 0

Reorder the terms:
3[4x + -4(-1 + y)] = 0
3[4x + (-1 * -4 + y * -4)] = 0
3[4x + (4 + -4y)] = 0

Reorder the terms:
3[4 + 4x + -4y] = 0
[4 * 3 + 4x * 3 + -4y * 3] = 0
[12 + 12x + -12y] = 0

Solving
12 + 12x + -12y = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + 12x + -12 + -12y = 0 + -12

Reorder the terms:
12 + -12 + 12x + -12y = 0 + -12

Combine like terms: 12 + -12 = 0
0 + 12x + -12y = 0 + -12
12x + -12y = 0 + -12

Combine like terms: 0 + -12 = -12
12x + -12y = -12

Add '12y' to each side of the equation.
12x + -12y + 12y = -12 + 12y

Combine like terms: -12y + 12y = 0
12x + 0 = -12 + 12y
12x = -12 + 12y

Divide each side by '12'.
x = -1 + y

Simplifying
x = -1 + y

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